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Mathematica 11.2 problem softmax license#
The Illustrative Mathematics name and logo are not subject to the Creative Commons license and may not be used without the prior and express written consent of Illustrative Mathematics. Spanish translation of the "B" assessments are copyright 2020 by Illustrative Mathematics, and are licensed under the Creative Commons Attribution 4.0 International License (CC BY 4.0). The second set of English assessments (marked as set "B") are copyright 2019 by Open Up Resources, and are licensed under the Creative Commons Attribution 4.0 International License (CC BY 4.0). Īdaptations and updates to IM 6–8 Math are copyright 2019 by Illustrative Mathematics, and are licensed under the Creative Commons Attribution 4.0 International License (CC BY 4.0).Īdaptations to add additional English language learner supports are copyright 2019 by Open Up Resources, and are licensed under the Creative Commons Attribution 4.0 International License (CC BY 4.0). OUR's 6–8 Math Curriculum is available at. It is licensed under the Creative Commons Attribution 4.0 International License (CC BY 4.0). IM 6–8 Math was originally developed by Open Up Resources and authored by Illustrative Mathematics®, and is copyright 2017-2019 by Open Up Resources. The softmax function provides a way of predicting a discrete probability distribution over the classes. Since \(c\) is a positive number, there is only one value it can take: When a classication task has more than two classes, it is standard to use a softmax output layer. Once the lengths of the legs are known, we use the Pythagorean Theorem to find the length of the hypotenuse, \(AB\), which we can represent with \(c\). The length of the vertical leg is 7, which can be seen in the diagram, but this is also the distance between the \(y\)-coordinates of \(A\) and \(B\) since \(|4 - \text-3|=7\). The length of the horizontal leg is 6, which can be seen in the diagram, but it is also the distance between the \(x\)-coordinates of \(A\) and \(B\) since \(|\text-8-\text-2|=6\). The horizontal line is labeled with the text "the absolute value of -8 minus -2 equals 6." The vertical line is labeled with the text "the absolute value of four minus negative three equals 7". The two lines meet at the point with coordinates negative 8 comma negative 3. A vertical line is drawn from Point B directly down and a horizontal line is drawn from Point A to the left until the two lines meet creating the third vertex of the triangle. Point A is located at negative 2 comme negative 3 and point B is located at negative 8 comma 4. Two of the vertices, point A and point B, of the triangle are labeled. On the y-axis, the numbers negative 3 through 4 are indicated.
On the x-axis, the numbers negative 8 through negative one are indicated. Description: A triangle is graphed in the coordinate plane with the origin labeled “O”.
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